L1981: No copydown created for initialized object“variable" . Initializatio

weifocus

  我是把整个程序都放在RAM中运行（这个程序是用来更新FLASH的），然后定义一个静态数组和uchar，就是出现这样的错识了，原来还可以更新FLASH的现在也不行了，但是程序没有死，其他流水灯都正常运行

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FSL_TICS_Robin

能否详细说下，比如什么编译环境、什么芯片。
或者上传你的工程

FSL_TICS_ZHJUN

看下这个有没有帮助:
L1981: No copydown created for initialized object . Initialization data lost.

Description
The named object is allocated in RAM and it is defined with some initialization values. But because no copy down information is allocated, the initialization data is lost.

Example
int i= 19;
int j;

When linking the code above with no startup code, then the linker does issue this warning for i as its initialization value 19 is not used.
Tips
If you do not want this object to be initialized, change the source or ignore the warning.
If you want this object to be located in a ROM area, check the source.
Is the object constant or not? "const char* test=..." is not const, use "const char* const test=..."
If you want this object to be initialized at runtime, you need some startup code. You can use the one provided with the compiler or take it as example and adapt it to your needs.
 

FSL_TICS_Fiona

不知道你用的哪款芯片，不过这个警告与芯片无关，从字面上看，你需要检查一下你新定义的静态数组和uchar。
 
静态数据默认放在RAM中，如果你不需要为其设置初始化值的话，就可以忽略这个警告。
 
但是如果为其了初始化值，那你的applicaion就不能脱离deugger 运行，因为掉电后， 初始值就丢失了。请修改linker 文件，将其初始值存在ROM中